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Home/ Questions/Q 8609401
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T03:52:25+00:00 2026-06-12T03:52:25+00:00

I have a class called HelloWorld where I create an object of Class Test

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I have a class called HelloWorld where I create an object of Class Test test = new Test();

then in the HelloWorld Class I have my main function and another:

public static int passMe(){
    System.out.println("running this function");
    return 1;
}

this is function im trying to pass. I pass it int test using the following:

test.getSomeFunction(new Callable<Integer>(){
              public Integer call(){
                  return passMe();
              }
          });

inside Test class I have:

    public void getSomeFunction(Callable<Integer> someFunction){
        System.out.println(someFunction);
    }

now all this works, but passMe() isn’t being run, rather I don’t know how to reference it.
if I print out someFunction, I get:

"HelloWorld$1@35a8767"

so my question is how do I go about running the function I got passed in, if I do someFunction() I get error message “he method someFunction() is undefined for the type Test”

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  1. Editorial Team
    Editorial Team
    2026-06-12T03:52:26+00:00Added an answer on June 12, 2026 at 3:52 am
        try {
            Integer result = callable.call();
        } catch (Exception e) {
            throw new IllegalStateException(e);
        }
    

    Exception have to be handled cause it is enforced by Callable definition.

    Note that you are not passing passMe function but callable object that can call it.

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