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Editorial Team
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Editorial Team
Asked: June 11, 20262026-06-11T11:19:04+00:00 2026-06-11T11:19:04+00:00

I have a class called photo. This class has 4 fields, one of while

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I have a class called photo. This class has 4 fields, one of while is called file. This file is of Django’s image field type.

I have a list composed of these image fields. I want to convert this python list in to a json string. If I call json.dumps(listData) on my list, then I get this error:

ImageFieldFile: photos/KObtu.jpg.

This seems sensible. The system represents the image field as a string that is not valid json. How can I override this output string? Alternatively, Is there a better way to do this?

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  1. Editorial Team
    Editorial Team
    2026-06-11T11:19:06+00:00Added an answer on June 11, 2026 at 11:19 am

    You can create a custom JSON Encoder class that knows how to encode ImageFieldFile:

    import json
    from django.db.models.fields.files import ImageFieldFile
    
    class EnhancedJSONEncoder(json.JSONEncoder):
        """
        JSONEncoder subclass that knows how to encode Django "ImageFieldFile"s.
        """
    
        def default(self, o):
            if isinstance(o, ImageFieldFile):
                # Treat ImageFieldFile as a unicode string
                return super(EnhancedJSONEncoder, self).default(unicode(o))
            else:
    
                return super(EnhancedJSONEncoder, self).default(o)
    

    You would then call json.dumps() as:

    json.dumps(listData, cls=EnhancedJSONEncoder))
    

    This assumes you’re wanting ImageFieldFile to be represented as a string

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