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Home/ Questions/Q 6891587
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T06:25:44+00:00 2026-05-27T06:25:44+00:00

I have a class: class Cat { Cat(); Tail longTail; } I am not

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I have a class:

class Cat {
   Cat();
   Tail longTail;
}

I am not sure about a proper way to write constructor for it. I don’t want to make longTail a pointer for non-related reason.

Cat::Cat() : longTail(length) {...} 

That one doesn’t fit because length is calculated in constructor, based on static members values at the moment of creation; (Poor practices upstream);


The question is

Cat::Cat() 
{
   int length;
   ...
   longTail = Tail(length);
}

How many times does creation and copying of Tail objects happen? They are CPU-expensive to both create and copy, and I need thousands of cats. It seems to me, this constructor first creates a default Tail object in longTail, after that it creates noname Tail object on the right of assignment, then runs operator= on longTail and noname Tail. Am I right? If yes, how should I write it instead to preserve CPU? I repeat: longTail needs a parameter, that is calculated in the constructor, and I can’t edit Tail class.

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  1. Editorial Team
    Editorial Team
    2026-05-27T06:25:44+00:00Added an answer on May 27, 2026 at 6:25 am

    In your second version your Tail-object will be default-initialized before the body of the constructor is run. In the body you create a second Tail-object and assign it to the first one.

    To enable correct construction in the initializer-list, you could wrap the computation of the parameters in a static member-function (since, as you said, it only depends in static members):

    class Cat {
    public:
        Cat() : longTail(calculateLength()) {...} 
    
    private:
        static int calculateLength() {}
    
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