Question

I have a class

  class TestFixture
    {
        public string a { get; set; }
        public int b { get; set; }
        public int c { get; set; }
        public string d { get; set; }

        public string e { get ; set ; }
        public int f { get; set; }
        public int g { get; set; }
        public bool h { get; set; }
        public string i { get; set; }
        public bool j { get; set; }
        public bool k { get; set; }

        public TestFixture()
        {
            e= dosomething(a, b);
            f= false;
            g = DateTime.Now.ToString("yyMMddhhmmss");
            h= TestName.Equals("1") && b.Equals("2") ? 1000 : 1;
            i= 10000000;
            j= a.Equals("FOT");
            k = false;
        }
    }

I want to define new TestFixture as SO

new TestFixture { a = "", b = 1, c=2, d="" };

while the rest of properties should be auto defined as it written in constructor.

Is it possible ?

Answer 1

Yes, this is possible. Using an object initializer does not skip calling the constructor.

TestFixture fixture = new TestFixture() // or just new TestFixture { ... }
{
    a = "", 
    b = 1, 
    c = 2, 
    d = "" 
};

This will call the constructor you’ve defined and then set a, b, c, and d in your object initializer.

---

Pop a breakpoint in your constructor and run your debugger. This is should show you how and when things in your code are called.

Debugging in Visual Studio

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Refactored:

public class TestFixture
{
    public string a { get; set; }
    public int b { get; set; }
    public int c { get; set; }
    public string d { get; set; }

    // dosomething should check for null strings
    public string e { get { return dosomething(a, b); } }
    public int f { get; set; }
    public int g { get; set; }
    public bool h 
    {
        get { return TestName.Equals("1") && b.Equals("2") ? 1000 : 1; }
    }
    public string i { get; set; }
    public bool j { get { return a != null && a.Equals("FOT"); } }
    public bool k { get; set; }

    public TestFixture(string a, int b, int c, string d) 
        : this() 
    {
        this.a = a;
        this.b = b;
        this.c = c;
        this.d = d;
    }

    public TestFixture()
    {
        f = false;
        g = DateTime.Now.ToString("yyMMddhhmmss");
        i = 10000000;
        k = false;
    }
}