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Home/ Questions/Q 9002545
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Editorial Team
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Editorial Team
Asked: June 16, 20262026-06-16T00:35:06+00:00 2026-06-16T00:35:06+00:00

I have a class: class WorkerThread { public: unsigned virtual run() { return 0;

  • 0

I have a class:

class WorkerThread
{
public:
    unsigned virtual run()
    {
        return 0;
    }
};

Defined in the header. Now in another class I create an object of this type:

WorkerThread **workerQueue;

Which is actually a pointer to pointer… OK, all good until now.
Now, how should I read this:

workerQueue = new WorkerThread*[maxThreads];

What is the meaning of the * after the ClassName (WorkerThread) and the array format?

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  1. Editorial Team
    Editorial Team
    2026-06-16T00:35:06+00:00Added an answer on June 16, 2026 at 12:35 am

    It’s an allocation of an array of WorkerThread pointers.

    For instance:

    size_t maxThreads = 3;
    WorkerThread** workerQueue = new WorkerThread*[maxThreads];
    

    workerQueue[0] is a WorkerThread*, as is WorkerThread[1] and WorkerThread[2].

    These pointers, currently have not been initialized.

    Later you may see something like this:

    for(size_t x = 0; x < maxThreads; ++x)
    {
       workerQueue[x] = new WorkerThread(...);
    
       //beginthreadex_, CreateThread, something....
    }
    

    I will tell you, that all of these raw pointers are just memory leaks waiting to happen unless carefully handled. A preferred method would be to use a std::vector to some smart pointer of WorkerThread objects.

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