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Home/ Questions/Q 3398514
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Editorial Team
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Editorial Team
Asked: May 18, 20262026-05-18T04:39:31+00:00 2026-05-18T04:39:31+00:00

I have a class ‘Collection’, which has an add method. The add method should

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I have a class ‘Collection’, which has an add method. The add method should only accept objects. So this is the desired behaviour:

$x=5;//arbitrary non-object
$obj=new Foo; //arbitrary object

$collection=new Collection;
$collection->add($obj); //should be acceptable arg, no matter the actual class
$collection->add($x); //should throw an error because $x is not an object

According to the PHP manual, one can typehint methods by prefacing the $arg with a class name. Since all PHP classes are children of stdClass, I figured this method signature would work:

public function add(stdClass $obj);

But it fails with “Argument must be an instance of stdClass”.

If I change the signature to a parent class defined by me, then it works:

class Collection {
  public function add(Base $obj){
    //do stuff
  }
}

$collection->add($foo); //$foo is class Foo which is an extension of Base

Does anyone know how to type hint for a generic object?

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  1. Editorial Team
    Editorial Team
    2026-05-18T04:39:31+00:00Added an answer on May 18, 2026 at 4:39 am

    Unlike Java’s Object class, PHP does not have a base class for objects. Objects do not inherit stdClass: it’s a default object implementation, not a base class. So, unfortunately, you can’t type hint for all objects in PHP. You have to do something like:

    class MyClass {
        public function myFunc($object) {
            if (!is_object($object))
                 throw new InvalidArgumentException(__CLASS__.'::'.__METHOD__.' expects parameter 1 to be object");
        }
    }
    

    Luckily, PHP already defines the InvalidArgumentException class for that purpose.

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