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Home/ Questions/Q 6821891
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T21:35:54+00:00 2026-05-26T21:35:54+00:00

I have a class (control), implementing ICustomTypeDescriptor, which is used both at design-time and

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I have a class (control), implementing ICustomTypeDescriptor, which is used both at design-time and run-time by PropertyGrid for customization. I need to expose different properties at design-time (standard controls properties like width, height and so on) and at run-time, when PropertyGrid is used in my program to change other properties of that control.

My code is like:

class MyControl : UserControl, ICustomTypeDescriptor
{
    //Some code..

    public PropertyDescriptorCollection GetProperties(Attribute[] attributes)
    {
        return GetProperties();
    }

    public PropertyDescriptorCollection GetProperties()
    {
        //I need to do something like this:
        if (designTime)
        { //Expose standart controls properties
            return TypeDescriptor.GetProperties(this, true);
        }
        else
        {
            //Forming a custom property descriptor collection
            PropertyDescriptorCollection pdc = new PropertyDescriptorCollection(null);
            //Some code..
            return pdc;
        }
    }
}

Is there an analog for a design-time flag in C#? Is it maybe better to use conditional compilation?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-26T21:35:55+00:00Added an answer on May 26, 2026 at 9:35 pm

    Check if DesignMode is true or false. It’s a property that belongs to the control base class.

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