Question

I have a class declared like this :

namespace nsp1
{

 class A
 {
  public :
   inline friend void DoSomething();

  private :
   A();

   int a;
 };

}

Like this, the function DoSomething() will be in the namespace nsp1.
Is there a way to declare this function to have it both inline friend and outside of the namespace?

Answer 1

Here is a solution:

 namespace nsp1
{
    class A;
}

inline void DoSomething(const nsp1::A & a);
 namespace nsp1
{

 class A
 {
  public :
   inline friend void ::DoSomething(const nsp1::A & a);

  private :
   A();

   int a;
 };

}

inline void DoSomething(const nsp1::A & a)
{
     std::cout<<a.a<<std::endl;//a.a is private!
}