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Home/ Questions/Q 1063523
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T18:47:42+00:00 2026-05-16T18:47:42+00:00

I have a class e.g. MyDataClass . I have a HashMap<String,MyDataClass> myMap; For each

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I have a class e.g. MyDataClass.
I have a HashMap<String,MyDataClass> myMap;
For each reference in the myMap, I also have some other MyDataClass references to the same object. To be specific:

MyDataClass c = new MyDataClass();
//configure c object with appropriate values
myMap.put("akeyvalue",c);
MyDataClass ref = c;

At this point ref and myMap.get("akeyvalue") refer to the same object in memory.
If I later do myMap.remove("akeyvalue") the entry in the hashmap will be removed, but the object ref will still refer to the same location. Essentially the value myMap.get("akeyvalue") still exists. How can I update it to null, so that it is synchronized to the hashmap? I.e. If I have distinct data structures/collections that refer to the same objects, what is the best pattern/design to use so as to keep them synchronized? In my small example, in the code that I do remove on myMap, I have no access to ref object. I must somehow find ref and null it. Generally, I could have a distict data structure e.g. List<MyDataClass> refs;

Thank you

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  1. Editorial Team
    Editorial Team
    2026-05-16T18:47:43+00:00Added an answer on May 16, 2026 at 6:47 pm

    You’ll have to do this manually. If you want a remove(..) on one collection to affect another:

    • extend HashMap (or any collection)
    • make a private Collection anotherCollection with setter and getter in your class
    • override remove(..), call super.remove(..) and also call anotherCollection.remove(..)
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