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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T15:54:33+00:00 2026-05-20T15:54:33+00:00

I have a class (for logging) which derives from std::ostream. Stripped down, it looks

  • 0

I have a class (for logging) which derives from std::ostream. Stripped down, it looks like this:

class bsgs : public std::ostream {
public:

  bsgs(const std::string& msg = "") {
    // some setup work
  }

  ~bsgs() {
    // some cleanup work
  }

  template<typename T>
  bsgs& operator<<(const T& rhs) {
    os << rhs;
    return *this;
  }

private:
  std::ostringstream os;
};

I wrote this class to do a few particular things I need like delta compression. Unfortunately, it doesn’t work. I need to pass it to a third-party library (with source, but fairly
large and messy) that provides a “set_out” function to direct its output to a std::ostream. The
set_out function prototype is exactly this:

void set_out(std::ostream *out=0, int level=1);

and if I call it as:

set_out(&std::cout, 3);

or

set_out(&std::cerr, 5);

I get exactly the expected behavior. However, if I write:

bsgs logger;
set_out(&logger, 3);

I can see that the logger’s constructor and destructor are called as expected but operator<< is never called. I’m not sure why, and I hope this is a simple question. If I can resolve this problem, I’m all set.

Does anyone know what exactly is going on? The problem seems to be that the library has no clue that I’m passing a pointer to a bsgs and not a std::ostream, but fixing the library to accept a wider range of objects than just std::ostream * looks like it might involve touching 500+ lines of code, which I’d like to avoid.

~~~~~~~~~~~~~~

Edit #1: I’m not sure if it is important, but the library has a virtual set_out() = 0; function at the top of its class hierarchy, which is implemented (identically, as far as I can see) in different subclasses. If I were writing the library I would have made set_out a (non-virtual) template function and provided with a specialization for std::ostream, but let users provide whatever they like so long as they define a usable operator<<. Making this change to the library looks like it will be a solid half a day of editing. Maybe there’s an easier way?

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  1. Editorial Team
    Editorial Team
    2026-05-20T15:54:33+00:00Added an answer on May 20, 2026 at 3:54 pm

    The library has no clue that you’re passing a pointer to a bsgs – you’re not overriding a virtual function, there’s no polymorphism involved.

    You may find that implementing a streambuf and replacing a streams associated stream buffer (ostream::rdbuf) is a more viable solution.

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