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Home/ Questions/Q 8782515
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T20:34:46+00:00 2026-06-13T20:34:46+00:00

I have a class in CS: class Model constructor: (objectParams) -> @object = ##object

  • 0

I have a class in CS:

class Model
  constructor: (objectParams) ->
    @object = ##object
    ###constructor

  baseObject: => {}
  validate: ko.computed =>
    console.log ko.toJS @object

The problem is with ‘validate’ it is a prototype property where the binding context of the ko.computed function should be the constructor but instead gets compiled to this:

Model.prototype.validate = ko.computed(function() {
  return console.log(ko.toJS(Model.object));
});

I want it to be binded to the constructor but the fat arrow => seems to be working only this way:

property: () =>

and this way it won’t work

  validate: =>
    ko.computed => console.log ko.toJS @object

because ko.computed can’t be defined inside a function

how can i solve?

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  1. Editorial Team
    Editorial Team
    2026-06-13T20:34:47+00:00Added an answer on June 13, 2026 at 8:34 pm

    Binding your function to the instance and “preprocessing” it works like this

    pipe = (fn)->
        return ->
            fn.apply(@, arguments)
    
    
    class A
        foo: pipe -> @bar()
        bar: -> ...
    

    from your pipe function (in your case ko.computed) return another function that wraps your initial function and calls it via .apply.

    No need for the fat arrow as your are calling apply with @

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