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Home/ Questions/Q 4067376
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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T16:14:30+00:00 2026-05-20T16:14:30+00:00

I have a class like so: class Qtree { public: Qtree(); Qtree(BMP img, int

  • 0

I have a class like so:

class Qtree
{
public:
    Qtree();
    Qtree(BMP img, int d);
private:
   class QtreeNode
   {
   public:
      QtreeNode* nwChild;  // pointer to northwest child
      QtreeNode* neChild;  // pointer to northeast child
      QtreeNode* swChild;  // pointer to southwest child
      QtreeNode* seChild;  // pointer to southeast child
      RGBApixel element;  // the pixel stored as this node's "data"

      QtreeNode();
      QuadtreeNode copy(QuadtreeNode & n);

   };

And so the question is on the copy method. It makes a copy of a given node and returns it.

QtreeNode Qtree::QtreeNode::copy(QtreeNode & n) {
   QtreeNode *newNode;
   //....
   return newNode;
}

And then I call copy from my Qtree copy constructor:

root=QtreeNode::copy(*tree.root); //each tree has a root pointer
//have also tried many different things here, but dont really know what to put

I get the following errors:

error: cannot call member function ‘Qtree::QtreeNode* Qtree::QtreeNode::copy(Qtree::QtreeNode&)’ without object

and

error: no matching function for call to ‘copy(Qtree::QtreeNode&)’
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-20T16:14:31+00:00Added an answer on May 20, 2026 at 4:14 pm

    try:

    static QuadtreeNode copy(QuadtreeNode & n);
    

    or better create copy constructor.

    copy is instance method, it means that it can be run only with object provided. It’s internal signature as a function is:

    QuadtreeNode copy(QtreeNode* this, QuadtreeNode & n);
    

    So you have to pass to parameters. Notation obj->copy(..) is used, but it is actually passing obj as first parameter.

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