Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 9229131
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: June 18, 20262026-06-18T05:29:49+00:00 2026-06-18T05:29:49+00:00

I have a class like so. public class Step<T> { public delegate void Act<T>();

  • 0

I have a class like so.

public class Step<T>
{
    public delegate void Act<T>();

    Act<T> _act;

    public Step(Act<T> action)
    {
        Contract.Requires(action != null);

        _act = action;
    }

    public void PerformStep()
    {
        _act.Invoke();
    }
}

My problem is as follows. I want the constructor of this class to be able to accept a delegate with the definition you see in the class. What I do not want is for that delegate to be a public member of my class. The alternative of this is to have a public delegate outside of the class but no other class but this one will need it. Is there a way I can make the delegate private?

If that solution is not possible is there an alternative? This step class is just a wrapper for delegates that are to be run sequentially. There is no need for a signature if I can have a more generic solution.

EDIT: More info for clarification.

The aim of this class it to be able to allow the user to do something like the following.

If I have a Class Car. This car will have methods like Drive, Stop, Turn etc. Using this Step Class the user of the Class should be able to create an instance of their class then do the following.

Car c = new Car();
Step<Car> step1 = new Step<Car>(c.TurnLeft);
Step<Car> step2 = new Step<Car>(c.Drive);
Step<Car> step3 = new Step<Car>(c.TurnRight);
//add steps to a collection
c.AddNewRoutine(collection of steps);
c.RunRoutine(identify which routine);

The steps will be added to a data structure that will allow them to be executed in order. The car class will contain a data structure that can hold these groups of steps. This then allows any class to be created and have the user set up steps for that class to take, without the class or main program having to hardcode the behaviour.

To finish. I need the step class to be as it is. I just do not want to allow public access to that delegate in any form as the only class who needs it is the Step class.

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-06-18T05:29:50+00:00Added an answer on June 18, 2026 at 5:29 am

    Remove the delegate alltogether and use an Action:

    private Action<T> _action;
    
    public Step(Action<T> action)
    {
       _action = action;
    }
    

    Edit:

    you can also have a simple System.Action with no type parameters

    private Action _action;
    
    public Step(Action action)
    {
       _action = action;
    }
    

    However, keep in mind that when doing this:

    var c = new Car();
    var step1 = new Step(c.TurnLeft);
    

    your’re tying the step1 to the actual instance c, you will not be able to reuse that step for another instance:

    var c2 = new Car(); //There's no way to call step1 on this =(
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I have a class like this public class foo { private void getThread() {
I have a class like this: public class Contest { List<ContestTeam> Teams { get;
I have a class like so: public abstract class ClassA<T> { protected ClassA(IInterface interface)
i have a class like [Serializable] public class MyClass { [XmlAttribute] public bool myBool
I have a class constructor like this: public JavoImageCorrectedDataHeader() { ByteBuffer buffer = ByteBuffer.allocate(this.size());
I have a base class like this: public class BaseResponse { public string ErrorMessage
I have a collection class like this: public class SomeDataCollection : List<ISomeData> { //
I have a class Client like that: public class Client { public Person Pers
I have a Client class like that: public class Client { public Person Pers
So I have a class with a wrapper class inside like so: public class

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.