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Home/ Questions/Q 7823045
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Editorial Team
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Editorial Team
Asked: June 2, 20262026-06-02T08:06:41+00:00 2026-06-02T08:06:41+00:00

I have a class like this public class StockCodes { public static boolean loaded

  • 0

I have a class like this

public class StockCodes
{

    public static boolean loaded = false;
    public static long lastUpdate = 0;
    private static long freq = 1000 * 60 * 60 * 24;
    public static HashMap<String, Stock> stockMap = new HashMap<String, Stock>();

    public static ArrayList<Stock> getCodes()
    {
        long now = System.currentTimeMillis();
        if ((StockCodes.loaded) && ((now - StockCodes.lastUpdate) < freq))
        {
            System.out.println(StockCodes.loaded);
            return stockList;

        } 
    else
        {
            HttpFetcher fetcher = new HttpFetcher();

        ....

            log.info("Load " + stockList.size() + " Stocks");
            StockCodes.loaded = true;
            StockCodes.lastUpdate = now;
            return stockList;
        }
    }


    public static void main(String[] args)
    {
        StockCodes.getCodes();
    }
}

When I run the java application , it outputs “true”. Telling us the stockcodes have loaded.
But when i debug the java appliction, it goes into the else. I do not understand why it runs in this way, especially why it outputs “true” the first time i run the application. Could someone else give me some help ,thank you ~

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-02T08:06:42+00:00Added an answer on June 2, 2026 at 8:06 am

    With the code given above, the control by default should always go in the else block and print nothing. You can verify it.

    Not if you have some more places where you call the getCodes() method, then it will differ. Having said this, please verify if there is no other place with a call to getCodes(). ie its invoked single time via main()

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