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Home/ Questions/Q 6362475
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T23:54:46+00:00 2026-05-24T23:54:46+00:00

I have a class MyMap which extends java.util.HashMap, the following code works as a

  • 0

I have a class MyMap which extends java.util.HashMap, the following code works as a block of statements but I don’t understand the use of the extra curly braces

MyMap m = new MyMap() {
  {
      put("some key", "some value");
  }
};

Now why do I need the extra curly braces, can’t I just do this (but this raises compile error)

MyMap m = new MyMap() {
    put("some key", "some value");
};
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  1. Editorial Team
    Editorial Team
    2026-05-24T23:54:47+00:00Added an answer on May 24, 2026 at 11:54 pm

    This:

    MyMap m = new MyMap() {
        ....
    };
    

    creates an anonymous inner class, which is a subclass of HashMap.

    This:

    {
        put("some key", "some value");
    }
    

    is an instance initializer. The code is executed when the instance of the anonymous subclass is created.

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