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Home/ Questions/Q 7089973
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Editorial Team
  • 0
Editorial Team
Asked: May 28, 20262026-05-28T07:59:16+00:00 2026-05-28T07:59:16+00:00

I have a class (Person) and a XML tree: <rows> <row> <number>1110</number> <name>Street</name> <value>First

  • 0

I have a class (Person) and a XML tree:

<rows>
    <row>
        <number>1110</number>
        <name>Street</name>
        <value>First Avenue</value>
        <description>First Avenue</description>
    </row>
    <row>
        <number>1120</number>
        <name>House number</name>
        <value>281</value>
        <description>281</description>
    </row>
    <row>
        <number>1160</number>
        <name>Postal</name>
        <value>2552AD</value>
        <description>2552AD</description>
    </row>
    <row>
        <number>1170</number>
        <name>Area</name>
        <value>Peru</value>
        <description>Peru</description>
    </row>
</rows>

The person class has attributes like street, house number, postal, and area. How do I fill this person object?

The problem in my query is that I dont know where to add:

where (string)c.Element("name") == "Street"

My code thus so far:

public class XMLparser
{
    public Person XMLparse(string path)
    {
        Person person = new Person();
        List<Person> ListPerson = new List<Person>();
        XDocument file = XDocument.Load(path);
        var query = from c in file.Descendants("row")
                    select new
                    {
                        c.Element("value").Value 
                    };

        // Loop through results
        foreach (var value in query)
        {
            person._street = value.Value;
            person._housenumber = value.Value;
            person._postal = value.Value;
            person._area = value.Value;
        }

        return person;
   }
}

What I want is to take from the xml and fill it in

person._street = value.Value;      //<-- First Avenue
person._housenumber = value.Value; //<-- 281
person._postal = value.Value;      //<-- 2552AD
person._area = value.Value;        //<-- Peru    

EDIT:

Here is the original XMl tree.

    <?xml version="1.0" encoding="utf-8" ?>
    <results>
      <person>
        <categories>
          <category>
            <number>01</number>
            <name>Person</name>
            <rows>
              <row>
                <number>0110</number>
                <name>ID</name>
                <value>value ID</value>
                <description>value ID</description>
              </row>
            </rows>
          </category>
          <category>
            <number>08</number>
            <name>Address</name>
            <rows>
              <row>
                <number>1110</number>
                <name>Street</name>
                <value>value street</value>
                <description>value street</description>
              </row>
              <row>
                <number>1120</number>
                <name>House number</name>
                <value>value House number</value>
                <description>value House number</description>
              </row>
              <row>
                <number>1160</number>
                <name>Postal</name>
                <value>value Postal</value>
                <description>value Postal</description>
              </row>
              <row>
                <number>1170</number>
                <name>Area</name>
                <value>value Area</value>
                <description>value Area</description>
              </row>
            </rows>
          </category>
        </categories>
      </person>
      <person>
        <categories>
          <category>
            <number>01</number>
            <name>Person</name>
            <rows>
              <row>
                <number>0110</number>
                <name>ID</name>
                <value>value ID</value>
                <description>value ID</description>
              </row>
            </rows>
          </category>
          <category>
            <number>08</number>
            <name>Address</name>
            <rows>
              <row>
                <number>1110</number>
                <name>Street</name>
                <value>value Street</value>
                <description>value Street</description>
              </row>
              <row>
                <number>1120</number>
                <name>House number</name>
                <value>value House number</value>
                <description>value House number</description>
              </row>
              <row>
                <number>1130</number>
                <name>House number extra</name>
                <value>value House number extra</value>
                <description>value House number extra</description>
              </row>
              <row>
                <number>1160</number>
                <name>Postal</name>
                <value>value Postal</value>
                <description>value Postal</description>
              </row>
              <row>
                <number>1170</number>
                <name>Area</name>
                <value>value Area</value>
                <description>value Area</description>
              </row>
            </rows>
          </category>
        </categories>
      </person>
    </results>
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-28T07:59:17+00:00Added an answer on May 28, 2026 at 7:59 am

    You can use this code:

    XDocument file = XDocument.Parse(xml);
    var persons
      = file.Descendants("rows")
            .Select (x => 
                {
                    var person = new Person();
                    var values = x.Descendants("row")
                                  .GroupBy(y => y.Element("name").Value, 
                                           y => y.Element("value").Value)
                                  .ToDictionary (y => y.Key, y => y.First());
    
                    foreach(var value in values)
                    {
                        switch (value.Key)
                        {
                            case "Street":
                                person.Street = value.Value;
                                break;
                            case "House number":
                                person.Housenumber = value.Value;
                                break;
                            case "Postal":
                                person.Postal = value.Value;
                                break;
                            case "Area":
                                person.Area = value.Value;
                                break;
                        }
                    }
                    return person;
                });
    

    It assumes that the XML can contain multiple rows tags, one for each person. It then gets the name and value of each row tag inside the rows tags and initializes a person with the values.

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