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Home/ Questions/Q 7960097
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Editorial Team
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Editorial Team
Asked: June 4, 20262026-06-04T04:40:26+00:00 2026-06-04T04:40:26+00:00

I have a class public class MyMain{ public static void main(String… arg){ Temp t

  • 0

I have a class

public class MyMain{
    public static void main(String... arg){
            Temp t = new Temp(){
                {
                    System.out.println(" instance initialize");
                }
            };

        }
    }

class Temp{
    int i;

    {
        i=9;
        System.out.println("Static"+i);
    }
    Temp(){
        System.out.println("Temp const "+i);
    }
}

When i execute the main method the output comes:

Static9
Temp const 9
instance initialize

Ideally, the blocks are executed before the constructor, but the inline initialization block is called after the Constructor. Why?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-04T04:40:27+00:00Added an answer on June 4, 2026 at 4:40 am

    You’re creating a subclass of Temp. For each class, any instance initializers are executed before the constructor body – but the superclass goes through initialization before the subclass initialization. So the execution flow is:

    • Initializers in Object
    • Constructor body in Object
    • Initializers in Temp
    • Constructor body in Temp
    • Initializers in anonymous class
    • Constructor body in anonymous class (none)

    I would strongly advise you to refactor any code which looked like this anyway – aim for clarity rather than cleverness.

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