Question

I have a class template:

template<int a, int b>
class foo {
};

I only want to instantiate it when a + b == 10.
Could I make this possible using std::enable_if?

Furthermore, if I have a data member in class foo:

template<int a, int b>
class foo {
    int c;
};

I only want to have c when a == 5.

How do I do that using std::enable_if?
Is this one the correct case to use std::enable_if?

Answer 1

I guess you can use static_assert better to enforce that constraint instead of enable_if

template<int a, int b>
class foo {
    static_assert(a+b==10, "a+b is not 10");
};

int main()
{
    foo<5,5> f; // will compile
    foo<1,5> f; // will fail to compile with error: a+b is not 10
    return 0;
}

enable_if is primarily used to conditionally remove functions and classes from overload resolution based on type traits and to provide separate function overloads and specializations for different type traits.