Question

I have a class Test with a peculiar data structure.
A member of class Test is a std::map where the key is a std::string and the mapped value is a struct defined as follows:

typedef struct {
  void (Test::*f) (void) const;
} pmf_t;

Initialization of the map is OK. The problem is when I am trying to call the function pointed. I made up a toy example reproducing the problem. Here it is:

#include <iostream>
#include <map>

using namespace std;

class Test;
typedef void (Test::*F) (void) const;
typedef struct {
  F f;
} pmf_t;


class Test
{
public:
  Test () {
    pmf_t pmf = {
      &Test::Func
    };
    m["key"] = pmf;
  }
  void Func (void) const {
    cout << "test" << endl;
  }
  void CallFunc (void) {
    std::map<std::string, pmf_t>::iterator it = m.begin ();
    ((*it).second.*f) (); // offending line
  }

  std::map<std::string, pmf_t> m;
};


int main ()
{

  Test t;
  t.CallFunc ();

  return 0;
}

Thanks in advance,
Jir

Answer 1

The name of the pmf_t type is f, so the first change is to remove the * to get second.f. That gives you a pointer-to-member value. To use a pointer-to-member, you need an instance. The only one you have available of the correct type is this, so use it with the ->* operator:

(this->*it->second.f)();

You need parentheses around the whole thing, or else the compiler thinks you’re trying to call it->second.f() (which isn’t allowed) and then applying the result to ->*.