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Home/ Questions/Q 6370833
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T00:58:52+00:00 2026-05-25T00:58:52+00:00

I have a class that contains a vector: class Foo { typdef std::vector<int> Vec;

  • 0

I have a class that contains a vector:

class Foo {
  typdef std::vector<int> Vec;
  Vec m_kids;
  void addKids(Vec::const_iterator begin, 
               Vec::const_iterator end) {
    m_kids.insert(m_kids.end(), begin, end);
  }
};

Is there any way to allow the following concise function calls? (Maybe by changing the addKids function above?)

int main() {
  Foo foo;
  foo.addKids(23,51,681);             // these...
  foo.addKids(3,6,1,4,88,2,4,-2,101); // ...would be nice?!
}

I suspect you can do it with C++0x vector initializer lists? But unfortunately, I cannot use C++0x. I can use Boost, though, if that helps.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-25T00:58:53+00:00Added an answer on May 25, 2026 at 12:58 am

    You can do this:

    Foo foo;
    foo << 3, 6, 1, 4, 88, 2, 4, -2, 101; //inserts all!
    

    For that you’ve to overloaded << and , operators, as:

    class Foo {
      typdef std::vector<int> Vec;
      Vec m_kids;
    public:
      Foo& operator<<(int item) {
        m_kids.push_back(item); return *this;
      }
      Foo& operator,(int item) {
        m_kids.push_back(item); return *this;
      }
    };
    

    Once you implement this, then you can also write:

    foo << 3 << 6 << 1 << 4 << 88 << 2 << 4 << -2 << 101; //inserts all!
    

    Even this,

    foo, 3, 6, 1, 4, 88, 2, 4, -2, 101; //inserts all!
    

    Or mix both as:

    foo << 3, 6, 1 << 4, 88, 2 << 4 << -2, 101; //inserts all!
    
    //and this too!
    foo,3 << 6, 1 << 4, 88, 2 << 4 << -2, 101; //inserts all!
    

    All are same!

    But mixing doesn’t look good. My preference is the very first one!

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