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Home/ Questions/Q 8613315
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T04:50:50+00:00 2026-06-12T04:50:50+00:00

I have a class that contains something like this Dictionary<int, Queue<string>> dict and then

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I have a class that contains something like this Dictionary<int, Queue<string>> dict and then I use TryGetValue:

Queue<string> value;
if (!dict.TryGetValue(3, out value))
    throw new MyException("...");

Is there an option not to explicitly define the value type, basically to avoid duplicity of typing it? In C++ STL containers, there is a value typedef value_type which can be used in such cases but I can’t seem to find similar feature in C#. Thanks.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-12T04:50:51+00:00Added an answer on June 12, 2026 at 4:50 am

    If you define yourself a nice helper method, you can wrap up the type specification:

    public static class Utility
    {
        public static TValue GetValueOrDefault<TKey,TValue>(
            this Dictionary<TKey, TValue> dictionary, 
            TKey key, 
            TValue @default = default(TValue))
        {
            TValue value;
            return dictionary.TryGetValue(key, out value)
                       ? value
                       : @default;
        }
    }
    

    Notice here we still have to explicitly type the value that’s going to be populated by TryGetValue, BUT from your caller you can just say:

    var value = dict.GetValueOrDefault(3);    // implicitly typed
    if (value == null)
        throw new MyException("...");
    

    Note that if null is a valid value in this context, you’ll need something else, but the same principle could be applied – use the fact that the compiler can infer types for generic methods to build a helper method to hide the explicit typing.

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