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Home/ Questions/Q 7841147
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Editorial Team
  • 0
Editorial Team
Asked: June 2, 20262026-06-02T16:02:19+00:00 2026-06-02T16:02:19+00:00

I have a class that has a const member, const pointer and enum class

  • 0

I have a class that has a const member, const pointer and enum class member,

My Questions for the sample code bellow:

  1. How to nuliffy a enum class member of “other”` in move constructor
    properly (what value to assign to it?)
  2. How to nullify a const pointer of “other”` in move constructor so
    that destructor of other does not delete a memory of object that is
    being constructed, and so that a pointer reamins valid?
  3. How to nullify a constant member of “other” in move constructor so
    that destructor of other does not get called?

enum class EnumClass
{
    VALUE0, // this is zero
    VALUE1
};

class MyClass
{
  public:
    MyClass() : 
        member(EnumClass::VALUE1),
        x(10.f),
        y(new int(4)) { }

    MyClass(MyClass&& other) : 
        member(other.member),
        x(other.x),
        y(other.y)
    {
        // Can I be sure that this approach will nullify a "member" and avoid
        // destructor call of other
        other.member = EnumClass::VALUE0;

        // Or shall I use this method?
        other.member = static_cast<EnumClass>(0);

        // ERROR how do I nullify "x" to avoid destructor call of other?
        other.x = 0.f;

        // ERROR the same here, delete is going to be called twice!
        other.y = nullptr;
    }

    ~MyClass() 
    {
        delete y;
    }

  private:
    EnumClass member;
    const float x;
    int* const y;
};
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-02T16:02:20+00:00Added an answer on June 2, 2026 at 4:02 pm

    You don’t need to worry about nullifying non-pointer types. They cannot be “freed” more than once, because their data is located inside of the class, not on the heap. Your const int pointer does need to be nullified, and it looks like you are doing that right.

    Take a look at this MDSN article for more info: http://msdn.microsoft.com/en-us/library/dd293665.aspx

    EDIT:

    If you declare an int* const y, you are declaring the pointer to be const. If you simply want the int to be const, declare it as const int* y. You cannot change the address of a pointer declared as int* const y.

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