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Home/ Questions/Q 8663339
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T16:57:53+00:00 2026-06-12T16:57:53+00:00

I have a class that has the following property: public Action<bool> Action { get;

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I have a class that has the following property:

public Action<bool> Action { get; private set; }

And I have a constructor that takes Action<bool> as an argument.

Now I want to add another constructor that accepts an object of type Action. How can I convert Action to Action<bool>? The bool-parameter should be true in this case.

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  1. Editorial Team
    Editorial Team
    2026-06-12T16:57:55+00:00Added an answer on June 12, 2026 at 4:57 pm
    public class Foo
    {
        public Foo(Action<bool> action)
        {
            // Some existing constructor
        }
    
        public Foo(Action action): this(x => action())
        {
            // Your custom constructor taking an Action and 
            // calling the existing constructor
        }
    }
    

    Now you could instantiate this class in 2 ways depending on which one of the 2 constructors you want to invoke:

    1. var foo = new Foo(x => { Console.WriteLine("Hello"); }); (calls the first ctor)
    2. var foo = new Foo(() => { Console.WriteLine("Hello"); }); (calls the second ctor)
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