Question

I have a class that implements an interface, and that interface extends another interface. The setting is like that:

interface A{
}

interface B extends A {
}

class C implements B {
}


$obj = new C();

I want to know which interfaces the object $obj implements. I tried to create a ReflectionClass object and then calling the getInterfaces method, but it only returns me the interface B:

$reflection = new ReflectionClass($obj);
print_r($reflection->getInterfaces());

I also tried to create a ReflectionClass object using the interface name, but when I call the getInterfaces() method, it returns an empty array.

Does any of you guys know how to get an interface name that extends a given interface?

Thanks a lot for your help,
Steve

Answer 1

You do not need Reflection for this. You can simply use

• class_implements — Return the interfaces which are implemented by the given class

Example for your code snippet:

var_dump(class_implements($obj));

Output:

array(2) {
  ["B"]=>
  string(1) "B"
  ["A"]=>
  string(1) "A"
}