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Home/ Questions/Q 4017402
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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T09:51:23+00:00 2026-05-20T09:51:23+00:00

I have a class that implements IEnumerator<string> . See below: public class MyClass :

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I have a class that implements IEnumerator<string>. See below:

public class MyClass : IEnumerator<string>
{
    public bool MoveNext()
    {
        //....
    }

    //Implement other required methods....

   //Confusion lies below:
   public string Current { get { return this.CurrentLine; } }

   //Why do I need to implement IEnumerator.Current?!  In my tests, it's not even called    during my iteration
   object IEnumerator.Current { get { throw new NotImplementedException(); } }

}   

Besides the fact that .Current property exists on both the IEnumerator<T> interface and the IEnumerator interface (which IEnumerator<T> inherits), what’s the point of implementing it? As seen above it’s not even called.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-20T09:51:24+00:00Added an answer on May 20, 2026 at 9:51 am

    IEnumerator<T> implements IEnumerator, so at the most basic level you have to fulfill the contract.

    Specifically as to why – what happens if someone does this:

    ((IEnumerator)yourInstance).Current
    

    They (usually) should expect to get a loosely-typed copy of the same value/reference returned from IEnumerator<T>‘s implementation. So in most cases, just return this.Current and don’t worry about it 🙂

    (FYI – returning this.Current is also good practice because it follows DRY and SRP – let the strongly-typed version of Current deal with the implementation details of what Current actually is.)

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