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Home/ Questions/Q 620835
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T18:48:27+00:00 2026-05-13T18:48:27+00:00

I have a class that is inherited from List<T> and also has some properties,

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I have a class that is inherited from List<T> and also has some properties, like this:

[Serializable]
public class DropList : List<DropItem>
{
    [XmlAttribute]
    public int FinalDropCount{get; set;}
}

This class is serialized to xml as part of a larger class:

[Serializable]
public class Location
{
    public DropList DropList{get; set;}
    ....
}

The problem is, serializer sees my list as a collection; the resulting XML contians only list elements, but not class properties (FinalDropCount in this case). This is an example of outputted XML:

<Location xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
    <DropList>
        <DropItem ProtoId="3" Count="0" Minimum="0" Maximum="0" />
        <DropItem ProtoId="4" Count="0" Minimum="0" Maximum="0" />
    </DropList>
    ....
</Location>

Is there some way to save both list contents and properties without resorting to implementing IXmlSerializable by hand?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-13T18:48:28+00:00Added an answer on May 13, 2026 at 6:48 pm

    You have other alternatives that you can consider.

    Alternative one – Move to composition instead of inheritance:

    public class DropInfo
    {
        [XmlArray("Drops")]
        [XmlArrayItem("DropItem")]
        public List<DropItem> Items { get; set; }
    
        [XmlAttribute]
        public int FinalDropCount { get; set; }
    }
    
    public class Location
    {
        public DropInfo DropInfo { get; set; }
    }
    

    Alternative two – Move the properties outside the collection:

    public class DropList : List<DropItem>
    {
    }
    
    public class Location
    {
        public DropList DropList { get; set; }
    
        [XmlAttribute]
        public int FinalDropCount { get; set; }
    }
    
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