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Home/ Questions/Q 7504853
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Editorial Team
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Editorial Team
Asked: May 29, 20262026-05-29T21:42:46+00:00 2026-05-29T21:42:46+00:00

I have a class that might throw any run-time exceptions during initialization. I want

  • 0

I have a class that might throw any run-time exceptions during initialization. I want the class to be a singleton since the cost of keeping several objects in memory is high. I am using that class in another class.

My use case is as follows:

  • I have to use a single instance of Controller.
  • Each instance of Parent must use the same Controller instance.
  • Controller
    constructor might throw exceptions.
  • If instantiation fails, I should
    retry to instantiate after sometime.

So I check if my Controller instance is null when I try to do a “get” on the Controller, if yes, I try to instantiate it again.

Following is my code:

class Parent
{
    private static volatile Controller controller;
    private static final Object lock = new Object();

    static
    {
        try
        {
            controller = new Controller();
        }
        catch(Exception ex)
        {
            controller = null;
        }
    }

    private Controller getController() throws ControllerInstantiationException
    {
        if(controller == null)
        {
            synchronized(lock)
            {
                if(controller == null)
                {
                    try
                    {
                        controller = new Controller();
                    }
                    catch(Exception ex)
                    {
                        controller = null;
                        throw new ControllerInstatntationException(ex);
                    }
                }
            }
        }
        return controller;
    }

    //other methods that uses getController() 
}

My question is, is this code broken? I read somewhere that the above code would be a problem in JVM 1.4 or earlier. Can you provide references/solutions? Please note that I am asking this question because there is a lot of confusion regarding this topic in the internet.

Thanks.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-29T21:42:48+00:00Added an answer on May 29, 2026 at 9:42 pm

    I believe it’s not broken, cause of volatile declaration. But imho better to avoid code like this. There is no guarantee, that this code will work with Java 8 for example. There are another way to create lazy singleton. I always (almost) use this method. First time faced with it in Java Concurrency in Practice book.

    public class Singleton {
            private Singleton() { }
    
            private static class SingletonHolder { 
                    public static final Singleton instance = new Singleton();
            }
    
            public static Singleton getInstance() {
                    return SingletonHolder.instance;
            }
    }
    

    I don’t know what you are doing in your code, it’s hard to say, how to tweak it. The most straightforward way, simply use synchronize method. Do you seriously want to receive some performance benefit using double-check-locking ? Is there bottle-neck in synch method ?

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