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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T07:48:30+00:00 2026-05-15T07:48:30+00:00

I have a class that represents undirected edges in a graph. Every edge has

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I have a class that represents undirected edges in a graph. Every edge has two members vertex1 and vertex2 representing the vertices it connects. The problem is, that an edge can be specified two directions. My idea was now to define the hash of an edge as the sum of the hashes of its vertices. This way, the direction plays no role anymore, the hash would be the same. Are there any pitfalls with that?

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  1. Editorial Team
    Editorial Team
    2026-05-15T07:48:30+00:00Added an answer on May 15, 2026 at 7:48 am

    I have had to solve a similar problem and found that using the sum of hashes as a hash results in too many collisions. The distribution of the sum of hashes is just not spread out enough.

    I found that using the product of hashes resulted in much less collisions. This of course depends on the nature of the hashes for the individual vertices.

    Set up a test bed and test a few symmetric hash functions and then choose the best based on collisions.

    You could try

    h(x,y) = x+y
    h(x,y) = x*y
    h(x,y)  = x * y + (x ^ y)
    h(x,y) = x *y + x + y
    

    where x^y = min(x,y)

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