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Home/ Questions/Q 540011
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T10:11:45+00:00 2026-05-13T10:11:45+00:00

I have a class that takes an action in it’s constructor. Example: public CustomClass(Action<Path>

  • 0

I have a class that takes an action in it’s constructor.

Example:

public CustomClass(Action<Path> insert)
{

  // logic here...

}

I currently instantiate this class using the following line of code:

var custom = new CustomClass((o) => LayoutRoot.Children.Add(o));

I want to modify the custom class to include an additional constructor, such as the following:

public CustomClass(Action<Path, TextBlock> insert)
{

  // logic here...

}

However, my knowledge of lambda expressions is pretty basic, so I can’t figure out how to instantiate the custom class, passing two parameters in the action to the new constructor.

Any help would be greatly appreciated.

Thanks.

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  1. Editorial Team
    Editorial Team
    2026-05-13T10:11:46+00:00Added an answer on May 13, 2026 at 10:11 am

    In order to pass 2 parameters to the action, just define the insert action as an Action<T,T2> and when you call it do it like this:

    var custom = new CustomClass((o,u) => {LayoutRoot.Children.Add(o); somethingElse(u)});
    
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