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Home/ Questions/Q 673201
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T00:34:11+00:00 2026-05-14T00:34:11+00:00

I have a class with a fields called a. In the class I have

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I have a class with a fields called “a”. In the class I have a method and in the list of arguments of this method I also have “a”. So, which “a” I will see inside of the method? Will it be the field or it will be the argument of the method?

public class myClass {
   private String a;
   // Method which sets the value of the field "a".
   public void setA(String a) {
     a = a;
   }
}

By the way, there is a similar situation. A method has some local (for method) variables whose names coincide with the names of the fields. What will the “see” the method if I refer to such a method-local variable inside the method (the field or the local variable)?

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  1. Editorial Team
    Editorial Team
    2026-05-14T00:34:11+00:00Added an answer on May 14, 2026 at 12:34 am

    The more local scope has the priority, so the parameter a will hide the field a. In effect, you set the value of parameter a to itself. The proper idiom to avoid name clashes (and improve readability) is to use this to explicitly mark the class member:

    public void setA(String a) {
      this.a = a;
    }
    

    The same is true for local variables vs member variables: local variables hide member variables with the same name.

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