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Home/ Questions/Q 6134705
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T17:23:21+00:00 2026-05-23T17:23:21+00:00

I have a class with a map, and I want to serialize the class

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I have a class with a map, and I want to serialize the class using boost serialize.

std::map<int, ComplicatedThing> stuff;

ComplicatedThing is derivable just by knowing the int. I want to serialize this efficiently. One way (ick, but works) is to make a vector of the keys and serialize the vector.

// illustrative, not test-compiled
std::vector<int> v;
std::copy(stuff.begin, stuff.end, std::back_inserter(v));
// or
for(std::vector<int> it = v.begin(); it != v.end(); it++)
    stuff[*it] = ComplicatedThing(*it);

// ...and later, at serialize/deserialize time
template<class Archive>
void srd::leaf::serialize(Archive &ar, const unsigned int version)
{
    ar & v;
}

But this is inelegant. Using BOOST_SERIALIZATION_SPLIT_MEMBER() and load/save methods, I think I should be able to skip the allocation of the intermediate vector completely. And there I am stuck.

Perhaps my answer lies in understanding boost/serialization/collections_load_imp.hpp. Hopefully there is a simpler path.

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  1. Editorial Team
    Editorial Team
    2026-05-23T17:23:21+00:00Added an answer on May 23, 2026 at 5:23 pm

    you can serialize it as list of ints (I don’t mean std::list) instead of serializing it as a container (map or vector). fist write number of elements and then them one by one, deserizalize accordingly. it’s 10 mins task. if you need this solution in many places, wrap map in your class and define serialization for it

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