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Home/ Questions/Q 7950491
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Editorial Team
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Editorial Team
Asked: June 4, 20262026-06-04T02:17:26+00:00 2026-06-04T02:17:26+00:00

I have a class with a static member that’s a pointer like so :

  • 0

I have a class with a static member that’s a pointer like so :

animation.h

class Animation
{
public:
    Animation();
    static QString *m;

};

animation.cpp

#include "animation.h"

QString* Animation::m = 0;

Animation::Animation()
{
}

When I try to initialize that ‘m’ pointer from another class like so :

Animation::m = new QString("testing");

It works.

But when I do it this way :

QString x("Testing");
Animation::m = &x;

The program crashes.

What is wrong with this second method ?

Also I would like to have that static pointer as private so I can make static getter and setter functions to it. The setter should use the second method as the ‘x’ will come in a parameter so I’m stuck.

Thanks for any help!

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  1. Editorial Team
    Editorial Team
    2026-06-04T02:17:27+00:00Added an answer on June 4, 2026 at 2:17 am

    I bet it’s not crashing on that line, but afterwards.

    The problem is that you’re taking the address of a variable located in automatic memory, and probably try to access it afterwards. The variable x will be destroyed when it’s scope ends, but Animation::m will still point to that memory (memory you no longer own after x went out of scope). This results in undefined behavior.

    Just like the following would be illegal:

    int* x = NULL;
    {
       int k = 3;
       x = &k;
    }
    *x = 4;
    

    Workaround assign to the value, not the pointer (provided it was previously assigned to a valid QString*):

    QString x("Testing");
    *(Animation::m) = x;
    
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