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Home/ Questions/Q 8928531
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T08:27:33+00:00 2026-06-15T08:27:33+00:00

I have a class with this code: package shop.orders.services.email private[services] class EmailService {…} Then

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I have a class with this code:

package shop.orders.services.email

private[services] class EmailService {...}

Then in a different package, I use that class:

package shop.ui

import shop.orders.services.email.EmailService

class PaymentConfirmation extends WithFacesContext {

    var emailService: EmailService = null

Looking at the generated bytecode, there is no sign of any access modifier, which makes sense, as Java does not support such access restrictions. So what happens if I create a library containing code like block one, and attempt to compile block two against the library – there is no chance that the compiler will fail, since the information is lost. Or is it contained in something like a manifest?

I’m using Scala 2.9.2.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-15T08:27:34+00:00Added an answer on June 15, 2026 at 8:27 am

    You could reference EmailService from Java, but not from Scala, because Scala stores the signature of the class as a scala.reflect.ScalaSignature annotation. The Scala compiler will fail with the following error:

    class EmailService in package email cannot be accessed in package shop.orders.services.email

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