Question

I have a code as follows:

int n;

int get_the_number();
void some_computations();

int main()
{
     n = get_the_number();
     some_computations()

     return(0);
}

• The get_the_number function get some input and returns the integer n, which after its call will not be modified.

• In the some_computation function there is the following code

  std::vector<my_struct> my_array;
  
  for(int i=0; i<n; i++)
  { 
       my_struct struct_temp;
  
       // fill struct_temp;
  
       my_array.push_back(struct_temp);
  }
  

Question: Since the size of my_array is known a priori, is it possible to replace the std::vector with a std::array?
Moreover, in the affirmative case, should I expect a gain in terms of efficiency?

I tried to replace the vector declaration with

 std::array<my_struct,n> my_array;

but I get an error: the size of the array must be constant.
Is there a way to avoid it?

Thank you very much.

Answer 1

std::array needs to know the size at compile time, which doesn’t apply to your code. So no, you cannot simply replace std::vector with std::array here, unless get_the_number() can return a constexpr For example.

constexpr int get_the_number() { return 42; }

int main()
{
  std::array<int, get_the_number()> a;
}

But presumably in your case int get_the_number() obtains a number determined at runtime.