Question

I have a code below, but i can’t put int to my buffer.

unsigned char  buffer[1024];
buffer[0] = 0x44;
u_long fd = htonl(VERSION);
memcpy(buffer+1, &fd, 4);

Can you help me?

Answer 1

In ntohl(buffer[1]); value of buffer[1] will be taken (a char) and will be casted into long.This will cause on a little endian machine to take value at &buffer[1] which is obviously 0 for value less than 2²⁴(unsigned) as you have called ntohl earlier which reverses byte order.

And if you are really interested to look into the buffer then try

int *f =(int*) (&buffer[1]);
printf("\n %u \n", ntohl(*f));//Also *f but then you have to paste it in calculator to see allignment