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Home/ Questions/Q 8680433
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T21:15:03+00:00 2026-06-12T21:15:03+00:00

I have a code in abstract class: public abstract class Job implements Runnable{ public

  • 0

I have a code in abstract class:

public abstract class Job implements Runnable{  
    public void start(Integer jobId) {                      
        try {
            new Thread(this).start();
        } catch (Exception e) {
            e.getMessage();
        }       
    }
}

class code:

public class Test extends Job {

    @Override
    public void run() {
        for(int i = 0; i < 5; i++) {
            try {
                Thread.currentThread();
                Thread.sleep(2000);
            } catch (InterruptedException e) {
                e.printStackTrace();
            }
            System.out.println("TEST");
        }       
    }
}

And in main I have:

public static void main (String[] args) throws MessagingException  
  {
      Test test = new Test();
      test.start(74); 
  }

So how can I pass parameter (jobId) from start method to run()?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-12T21:15:04+00:00Added an answer on June 12, 2026 at 9:15 pm

    In the Job.start() method, store the value in a member variable, so that you can access it in the run() method later, when the thread is started.

    public abstract class Job implements Runnable {
        protected Integer jobId;
    
        public void start(Integer jobId) {
            this.jobId = jobId;
            try {
                new Thread(this).start();
            } catch (Exception e) {
                e.getMessage();
            }       
        }
    }
    
    public class Test extends Job {
        @Override
        public void run() {
            System.out.println(jobId);
        }
    }
    
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