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Home/ Questions/Q 8042187
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Editorial Team
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Editorial Team
Asked: June 5, 20262026-06-05T04:29:36+00:00 2026-06-05T04:29:36+00:00

I have a code in VC2010 which I’ve reduced to a small example. Test.h:

  • 0

I have a code in VC2010 which I’ve reduced to a small example.

Test.h:

#pragma once

template <typename TPixel>
struct Image
  {
  typedef TPixel PixelType;
  };

template <typename TImageType>
struct Operation
  {
  void DoOperation()
    {
    ImageType::PixelType value = 0;   
// I've done a misprint here. It should be TImageType::PixelType
    }
  };

Test.cpp:

void Test()
  {
  typedef Image<char> ImageType;

  Operation<ImageType> op;
  op.DoOperation();
  }

As I expected, that produces an error.

test.h(14): error C2653: 'ImageType' : is not a class or namespace name

Now, let’s change test.cpp just a little bit.

typedef Image<char> ImageType;

void Test()
  {
  Operation<ImageType> op;
  op.DoOperation();
  }

Now it compiles! Surprisingly enough, ImageType in DoOperation() now matches with the global typedef in test.cpp.

My question: why does it compile? Is that a Visual C++ bug or a standard behavior?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-05T04:29:38+00:00Added an answer on June 5, 2026 at 4:29 am

    I take it that test.cpp includes test.h before the typedef, so it’s actually

    #include "test.h"
    typedef Image<char> ImageType;
    
    void Test()
      {
      Operation<ImageType> op;
      op.DoOperation();
      }
    

    Completed like this, it is indeed a bug, or standard nonconforming behavior with regard to two phase lookup. Names that do not depend on a template parameter should be resolved relative to the point of declaration of the template.

    I guess this is known behavior.

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