Question

I have a code like this

<?php

$getLeftSide = 'select * from leftmenu';

$result = $db -> query ($getLeftSide) or die ("$db->error");

if ($result) {

    while ($row = $result -> fetch_object()) {

        $getCat = $row -> left_item_cat;



        if ($getCat == 1) {
    echo "<div class='left_main_cat'>Web and Desigen</div>";
    echo "<a href='index.php?learn_id= $row->left_item_link'><div class='left_label_sub'>$row->left_item_name</div></a>";

        }
      }
    }



?>

I need to echo this line one time

echo "<div class='left_main_cat'>Web and Design</div>";

of course it’s under the while loop so it print it self many times
is there is a why to solve this and print this line one time only.

Answer 1

As Ben suggests, the easiest and clearest solution is to use a boolean check variable:

$catFound = FALSE;
while ($row = $result -> fetch_object()) {

    $getCat = $row -> left_item_cat;

    if ($getCat == 1) {
        // We only want this category printed for the first category,
        // if it exists.
        if(!$catFound) { 
            echo "<div class='left_main_cat'>Web and Desigen</div>";
            $catFound = TRUE;
        }
        echo "<a href='index.php?learn_id= $row->left_item_link'><div class='left_label_sub'>$row->left_item_name</div></a>";
    }
}

Although it seems better to use a boolean variable and a comment to make clear your intent.