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Home/ Questions/Q 3498514
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Editorial Team
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Editorial Team
Asked: May 18, 20262026-05-18T12:29:57+00:00 2026-05-18T12:29:57+00:00

i have a code like this <script>$(document).ready(function(){ var myPlayList = []; //document.write(whatTo); //New instance

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i have a code like this

<script>$(document).ready(function(){

        var myPlayList = []; 

        //document.write(whatTo);
        //New instance of jPlayerSkin
        var skin = new jPlayerSkin( '#jplayer_container' , myPlayList );

        //Start the player
        skin.initialize();
 });

</script>

and i have function , which is function updatePlaylist(song,title,url) { /* code */ }

Now all i want is to execute this updatePlaylist function in document.ready because in this function i also call skin.add() , which is available in document.ready only. But when i place the function in document.ready() , i can’t execute it, and if i put it outside, i can execute the function but it can’t access skin.add().

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-18T12:29:58+00:00Added an answer on May 18, 2026 at 12:29 pm

    move var myPlayList = []; and var skin = null outside of the document.ready, try again with updatePlaylist(song,title,url)in document.ready

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