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Home/ Questions/Q 7644997
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T09:49:37+00:00 2026-05-31T09:49:37+00:00

I have a code snippet, as follows. #!/bin/bash filename=tmp_list_filenames line_index=0 cat $filename | while

  • 0

I have a code snippet, as follows.

#!/bin/bash
filename="tmp_list_filenames"
line_index=0
cat $filename | while read processed_data_filename; do
    line_index=$(($line_index + 1))
    var="haha$line_index"
done
echo "thevar:$var"

The output is simply thevar:, or $var is not raechable outside while loop. Why is it the case here? I also tried replace while codeline with while [ $line_index -lt 3 ]; do, as follows,

#!/bin/bash
filename="tmp_list_filenames"
line_index=0
while [ $line_index -lt 3 ]; do
    line_index=$(($line_index + 1))
    var="haha$line_index"
done
echo "thevar:$var" 

Then, it prints thevar:haha4. It is very strange to me, can anyone explain this?

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  1. Editorial Team
    Editorial Team
    2026-05-31T09:49:38+00:00Added an answer on May 31, 2026 at 9:49 am

    Classic example of UUOC. By putting the while loop in a pipeline, it is running in a subprocess. There is no need for the pipe:

    while ...; do ...; done < $filename
    

    should solve the problem

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