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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T06:20:36+00:00 2026-05-14T06:20:36+00:00

I have a code to concatenate strings. However, for some reason, the final string

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I have a code to concatenate strings. However, for some reason, the final string is not a combination of the required strings. Consider the following code :

//cusEmail is of type String[]
String toList = "";
for(i=0; i < cusEmail.length - 1; i++) {
    toList.concat(cusEmail[i]);
    toList.concat("; ");
    System.out.println(cusEmail[i]);
}
toList.concat(cusEmail[i]);
System.out.println(toList);

The first sout statement displays the strings in cusEmail[i] correctly. However, once concatenated, the second sout displays a blank / empty. Any reason for this? Am i concatenating it correctly?

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  1. Editorial Team
    Editorial Team
    2026-05-14T06:20:37+00:00Added an answer on May 14, 2026 at 6:20 am

    String objects are immutable. Calling concat on toList will not change the value of the toList object. Instead concat will return a different String object that is a concatenation of the two strings. For your example, you will want to store the result of each of the calls to concat in the toList variable.

    For example,

    toList = toList.concat(cusEmail[i]);
    

    An alternative to using the concat method would be to use the concatenation operator. This might be a little nicer to read.

    toList = toList + cusEmail[i];
    

    Note, however, that each time one string is concatenated onto another string, a new String object needs to be created that contains copies of the information in the two original strings. This can be a costly way of building a string when it is done over and over in a loop such as what you have. This is true whether you use the concat method or the concatenation operator. An alternative is to use a StringBuilder object to build your string.

    StringBuilder toList = new StringBuilder();
    for(i=0; i < cusEmail.length - 1; i++) {
        toList.append(cusEmail[i]);
        toList.append("; ");
        System.out.println(cusEmail[i]);
    }
    toList.append(cusEmail[i]);
    System.out.println(toList.toString());
    
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