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Home/ Questions/Q 9156713
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Editorial Team
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Editorial Team
Asked: June 17, 20262026-06-17T12:50:09+00:00 2026-06-17T12:50:09+00:00

I have a collection called season that looks like this: [ { week: 1,

  • 0

I have a collection called season that looks like this:

[ 
  { 
    week: 1,
    matchups: [ 
        {
            home : ObjectId("1"),
            away : ObjectId("2")
        },
        {
            home : ObjectId("3"),
            away : ObjectId("4")
        },

    ],
    _id: 50fc50c9ce87149ee3000007 
  },
  { 
    week: 2,
    matchups: [ 
        {
            home : ObjectId("3"),
            away : ObjectId("1")
        },
        {
            home : ObjectId("2"),
            away : ObjectId("4")
        },
    ],
    _id: 50fc50c9ce87149ee3000008 
  }
]

I’m trying to get all of the matchups where the home OR away team is ObjectId(“1”). I want the return to look like this:

[ 
  { 
    week: 1,
    matchups: [ 
        {
            home : ObjectId("1"),
            away : ObjectId("2")
        }

    ],
    _id: 50fc50c9ce87149ee3000007 
  },
  { 
    week: 2,
    matchups: [ 
        {
            home : ObjectId("3"),
            away : ObjectId("1")
        }
    ],
    _id: 50fc50c9ce87149ee3000008 
  }
]

Is it possible to get this result using on db.season.find()?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-17T12:50:11+00:00Added an answer on June 17, 2026 at 12:50 pm

    As long as you have at most one potential matchups element to match, you can use the $elemMatch projection operator to do this:

    db.seasons.find(
        {$or: [{'matchups.home': ObjectId("1")},{'matchups.away': ObjectId("1")}]}, 
        {week: 1, matchups: {
            $elemMatch: {$or: [{home: ObjectId("1")},{away: ObjectId("1")}]}
        }});
    

    Same caveat as Wes regarding the invalidity of ObjectId("1").

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