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Home/ Questions/Q 6140949
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T18:11:00+00:00 2026-05-23T18:11:00+00:00

I have a collection of objects that each defined by a particular group. How

  • 0

I have a collection of objects that each defined by a particular “group”. How can I write a LINQ query to produce a count of each object grouped by “group”.

As an example, lets say I have the following classes;

public class Release 
{
     int ReleaseNumber; 

     public ReleaseDetails[] details;

}

public class ReleaseDetails
{
    string Group;

    // other details omitted
}

For a given release, I’d like to be able to produce output like;

Release number 1 contains the following details;
 - 17 records in Group A
 - 12 records in Group B
 - 6 records in Group C

Any help is much appreciated.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-23T18:11:00+00:00Added an answer on May 23, 2026 at 6:11 pm

    You can do something like

    var q = from d in r.Details
                group d by d.Group into counts
                select new { Count = counts.Count(), Group = counts.Key };
    

    Full example:

            Release r = new Release
            {
                ReleaseNumber = 1
                ,
                Details = new ReleaseDetails[]
                {
                    new ReleaseDetails { Group = "a"},
                    new ReleaseDetails { Group = "a"},
                    new ReleaseDetails { Group = "b"},
                    new ReleaseDetails { Group = "c"},
                    new ReleaseDetails { Group = "d"},
                    new ReleaseDetails { Group = "d"},
                    new ReleaseDetails { Group = "e"},
    
                }
            };
    
            var q = from d in r.Details
                    group d by d.Group into counts
                    select new { Count = counts.Count(), Group = counts.Key };
    
            foreach (var count in q)
            {
                Console.WriteLine("Group {0}: {1}", count.Group, count.Count);
            }
    
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