Question

I have a column A which contain 4 fields separated by ‘/’

example:  234-12-343/653423/MANAGER/[e-mail]

Wonder how can i extract field index 2 ? so the final output will be 653423.

(My idea is using regular expression, but have no idea how to do it)

*Database is Oracle 10g

I was able to come out these query. Thanks for the help

select substr(ColumnA',
          regexp_instr(ColumnA,'[\/]',1,1,0) + 1,
          regexp_instr(ColumnA,'[\/]',1,2,0) - regexp_instr(ColumnA,1,1,0) - 1  ) 
          as test from dual

Answer 1

substr(column_a, instr(column_a,'/',1,1) + 1, instr(column_a,'/',1,2) - instr(column_a,'/',1,1) - 1)

instr(column_a,'/',1,1) searches for the first occurance of /
instr(column_a,'/',1,2) searches for the second occurance of /

the substr then extracts everything between the two positions