Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • Home
  • SEARCH
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 5990687
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 22, 20262026-05-22T23:16:46+00:00 2026-05-22T23:16:46+00:00

I have a column in my table that has a few different values, of

  • 0

I have a column in my table that has a few different values, of which I verified by using a group by.

When I do something like this it returns a number amount:

SELECT COUNT(*) FROM table WHERE age='';

However when I do this it always returns 0 even though that is incorrect:

SELECT COUNT(*) FROM table WHERE age=NULL;

Any idea why this is returning 0 when it should be returning the correct result?

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-22T23:16:47+00:00Added an answer on May 22, 2026 at 11:16 pm
    SELECT COUNT(*) FROM table WHERE age IS NULL;
    

    Read 3.3.4.6. Working with NULL Values

    To test for NULL, you cannot use the
    arithmetic comparison operators such
    as =, <, or <>.

    Use the IS NULL
    and IS NOT NULL operators instead:

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I have an old table with a few rows that has a datetime column.
I have a legacy mysql database and there's this table which has a few
I have a table that has a processed_timestamp column -- if a record has
Suppose I have a database table that has a timedate column of the last
Suppose I have a table called Companies that has a DepartmentID column. There's also
I have a user table in my mysql database that has a password column.
I need a select from table which does not have column that tells when
I have some code in my application that looks something like this: char *hash
My table has few fields with an amount column of type decimal. This column
I've got a few tables that all have the same column domainID which basically

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.