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Home/ Questions/Q 3681112
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Editorial Team
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Editorial Team
Asked: May 19, 20262026-05-19T03:39:19+00:00 2026-05-19T03:39:19+00:00

I have a column which should have 3 possible values (for example ‘A’, ‘B’,

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I have a column which should have 3 possible values (for example ‘A’, ‘B’, ‘C’).
It is conventional to use enum for such kind of things, but since many tables in my DB will have such column, I would like to define a default value (‘C’) for type, representing this enum.

(AFAIK without any additional definitions, I need to write something like this:

%COLUMN% %ENUM_TYPE% NOT NULL DEFAULT enum_first(null::%ENUM_TYPE%),

every time i need such enum)

CREATE TYPE ... statement does not allow to define default value, but CREATE DOMAIN ... does.

I tried a little trick: CREATE TYPE zzz_enum AS ENUM (...); CREATE DOMAIN zzz AS zzz_enum DEFAULT 'A';, but query with comparison of %zzz column% = 'A' results in error:

... operator %zzz% = undefined ...

How can I define comparison operator for domain ‘by-hand’ or create a custom type, which will:

  • Have a list of possible values, which I could get through query
  • Have one of those values as a default value
  • Be a identifier, which I could use like any regular SQL type in table definition

Thanks in advance!

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  1. Editorial Team
    Editorial Team
    2026-05-19T03:39:20+00:00Added an answer on May 19, 2026 at 3:39 am

    This ought to work, but it doesn’t. I think it’s a bug.

    Follow the discussion here: http://archives.postgresql.org/pgsql-bugs/2011-01/msg00082.php

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