Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Lost your password? Please enter your email address. You will receive a link and will create a new password via email.
Please briefly explain why you feel this question should be reported.
Please briefly explain why you feel this answer should be reported.
Please briefly explain why you feel this user should be reported.
I have a column with =IF(E2=”W “,H2,IF(I2<>””,I2,””)) in it.
It displays values but when I take an average of the column, it comes up with a divide by zero error.
Is there a special type of average function I need to use for this?
I assume that H2 and/or I2 are numbers? Perhaps those numbers are text formatted (in which case AVERAGE, not finding any true numbers will return #DIV/0! error). Try converting like this:
=IF(E2="W ",H2+0,IF(I2<>"",I2+0,""))+0 will convert a text-formatted number to an actual number, then your AVERAGE function should work