Question

I have a complete XML document in a string and would like a Document object. Google turns up all sorts of garbage. What is the simplest solution? (In Java 1.5)

Solution Thanks to Matt McMinn, I have settled on this implementation. It has the right level of input flexibility and exception granularity for me. (It’s good to know if the error came from malformed XML – SAXException – or just bad IO – IOException.)

public static org.w3c.dom.Document loadXMLFrom(String xml)     throws org.xml.sax.SAXException, java.io.IOException {     return loadXMLFrom(new java.io.ByteArrayInputStream(xml.getBytes())); }  public static org.w3c.dom.Document loadXMLFrom(java.io.InputStream is)      throws org.xml.sax.SAXException, java.io.IOException {     javax.xml.parsers.DocumentBuilderFactory factory =         javax.xml.parsers.DocumentBuilderFactory.newInstance();     factory.setNamespaceAware(true);     javax.xml.parsers.DocumentBuilder builder = null;     try {         builder = factory.newDocumentBuilder();     }     catch (javax.xml.parsers.ParserConfigurationException ex) {     }       org.w3c.dom.Document doc = builder.parse(is);     is.close();     return doc; } 

Answer 1

This works for me in Java 1.5 – I stripped out specific exceptions for readability.

import javax.xml.parsers.DocumentBuilderFactory; import javax.xml.parsers.DocumentBuilder; import org.w3c.dom.Document; import java.io.ByteArrayInputStream;  public Document loadXMLFromString(String xml) throws Exception {     DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();      factory.setNamespaceAware(true);     DocumentBuilder builder = factory.newDocumentBuilder();      return builder.parse(new ByteArrayInputStream(xml.getBytes())); }