Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 3241534
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 17, 20262026-05-17T18:12:36+00:00 2026-05-17T18:12:36+00:00

I have a controller action that uses a sql query: $tag = $this->params[‘tag’]; $this->set(‘projects’,

  • 0

I have a controller action that uses a sql query:

    $tag = $this->params['tag'];

    $this->set('projects', $this->Project->query('SELECT * FROM projects INNER JOIN projects_tags ON projects.id = projects_tags.project_id INNER JOIN tags on projects_tags.tag_id = tags.id WHERE tags.tag LIKE $tag'));

As you can see at the end I want to use a where clause with the $tag variable but I’m not sure how the syntax would go. As I’m getting the error

Unknown column '$tag' in 'where clause'

Can someone steer me in the right direction?

Ta,

Jonesy

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-17T18:12:36+00:00Added an answer on May 17, 2026 at 6:12 pm

    Modify your query as:

    $this->set('projects',
    $this->Project->query("SELECT * FROM projects
                           INNER JOIN projects_tags
                           ON projects.id = projects_tags.project_id
                           INNER JOIN tags ON projects_tags.tag_id = tags.id
                           WHERE tags.tag LIKE '" . $tag . "'") //problem was here
                         );
    

    and it will work.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

No related questions found

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.