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Asked: 2026-05-31T12:16:53+00:00

I have a CSV like this Parameter Values,Count,% of Results david;dd@gmail.com;10300 , 15 ,

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I have a CSV like this

Parameter Values,Count,% of Results
" david;dd@gmail.com;10300 "," 15 "," 50.0% "
" david;dd@gmail.com;12300 "," 15 "," 50.0% "
" davidk;dk@gmail.com;32300 "," 15 "," 50.0% "
" joe;joe@gmail.com;9200 "," 15 "," 50.0% "
" john;jj@gmail.com;1500 "," 15 "," 50.0% "

I want to get the line that has the highest number value, in this case 32300

I already made an attempt at this but it uses several commands

export max=$(awk -F, '{split($1,a,";"); print a[3] }' contestEntryTest.csv | tr -d ' "' | sort -nr | head -n 1) ; grep $max contestEntryTest.csv

How can i do the above in less commands or one command, how would a more experienced bash programmer do the above problem, just for the learning experience.
Cheers!

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1 Answer

  1. Editorial Team

    You can use sort, if the file is demo.csv, then

    sort -t ';' -k3 -n demo.cvs|tail -n 1
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